A case that sideways.vim ignores

[you-n-g]

Hi,
Sideways is realy a great plugin that saves me a lot of time.
It works as what I expected most of the time.

But it ignores a case that happens in my daily work.

a, b, c = 1, 2, 3

Sideways can't move a, b or c left or right.
There is the same issue with 1, 2 or 3.

Thanks in advance if you can consider such case!

[AndrewRadev]

Sideways is realy a great plugin that saves me a lot of time.

Thanks, I'm happy to hear that.

The problem with supporting this use case is that, currently, sideways needs to know how a list starts in order to decide how to work with it. For instance, if you have foo(1, 2, 3), the plugin looks for an opening ( and if it finds it, considers it the start of a list with comma-separated items. Here's the relevant definition even:

sideways.vim/plugin/sideways.vim

Lines 39 to 42 in 19c5a21

	\ 'start': '(\_s*',
	\ 'end': ')',
	\ 'delimiter': ',\_s*',
	\ 'brackets': ['([{''"', ')]}''"'],

Could the "start" be defined simply as the start of the line? Sort of. I've created a branch, variable-assignments, which implements this, with some tweaks. The problem is, it breaks a lot of other cases, for instance:

foo = [
  one, two,
  three, four
]

With the cursor on the last item, the plugin finds a valid start at the beginning of three, four and only works on that area. You'd think that it would give up because it doesn't find an ending =, but it finds a closing bracket, and the behaviour of the plugin is to consider that an "end", so that, for instance, if you have something like [1, 2, function_call 3, 4], the function_call would be detected correctly.

I don't have a good solution to this. The branch is there, and you could experiment with it, but I think it'll break too many other cases. I'll keep thinking about a possible solution, but the general rule of the plugin is "detect the type of list based on the start".

[you-n-g]

Is it OK to make it only works when the beginning and ending are in the same sideways_definition dict?

In your case, it find a closing bracket as the ending, but it is not paired with the previous found beginning(the start of the line).

Thanks.