README_EN.md

comments	difficulty	edit_url	rating	source	tags
true	Medium	https://github.com/doocs/leetcode/edit/main/solution/2300-2399/2317.Maximum%20XOR%20After%20Operations/README_EN.md	1678	Biweekly Contest 81 Q3	Bit Manipulation Array Math

2317. Maximum XOR After Operations

中文文档

Description

You are given a 0-indexed integer array nums. In one operation, select any non-negative integer x and an index i, then update nums[i] to be equal to nums[i] AND (nums[i] XOR x).

Note that AND is the bitwise AND operation and XOR is the bitwise XOR operation.

Return the maximum possible bitwise XOR of all elements of nums after applying the operation any number of times.

 

Example 1:

Input: nums = [3,2,4,6]
Output: 7
Explanation: Apply the operation with x = 4 and i = 3, num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2.
Now, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4 XOR 2 = 7.
It can be shown that 7 is the maximum possible bitwise XOR.
Note that other operations may be used to achieve a bitwise XOR of 7.

Example 2:

Input: nums = [1,2,3,9,2]
Output: 11
Explanation: Apply the operation zero times.
The bitwise XOR of all the elements = 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11.
It can be shown that 11 is the maximum possible bitwise XOR.

 

Constraints:

• 1 <= nums.length <= 105
• 0 <= nums[i] <= 108

Solutions

Solution 1

Python3

class Solution:
    def maximumXOR(self, nums: List[int]) -> int:
        return reduce(or_, nums)

Java

class Solution {
    public int maximumXOR(int[] nums) {
        int ans = 0;
        for (int x : nums) {
            ans |= x;
        }
        return ans;
    }
}

C++

class Solution {
public:
    int maximumXOR(vector<int>& nums) {
        int ans = 0;
        for (int& x : nums) {
            ans |= x;
        }
        return ans;
    }
};

Go

func maximumXOR(nums []int) (ans int) {
	for _, x := range nums {
		ans |= x
	}
	return
}

TypeScript

function maximumXOR(nums: number[]): number {
    let ans = 0;
    for (const x of nums) {
        ans |= x;
    }
    return ans;
}