Write a function called sumIntervals/sum_intervals() that accepts an array of intervals, and returns the sum of all the interval lengths. Overlapping intervals should only be counted once.
Intervals are represented by a pair of integers in the form of an array. The first value of the interval will always be less than the second value. Interval example: [1, 5] is an interval from 1 to 5. The length of this interval is 4. Overlapping Intervals
List containing overlapping intervals:
[ [1,4], [7, 10], [3, 5] ]
The sum of the lengths of these intervals is 7. Since [1, 4] and [3, 5] overlap, we can treat the interval as [1, 5], which has a length of 4.
sumIntervals( [ [1,2], [6, 10], [11, 15] ] ); // => 9
sumIntervals( [ [1,4], [7, 10], [3, 5] ] ); // => 7
def sum_of_intervals(intervals):
sum_set = set()
for i in range(len(intervals)):
for j in range(intervals[i][0],intervals[i][1]):
sum_set.add(j)
return len(sum_set)