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103.二叉树的锯齿形层次遍历.js
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103.二叉树的锯齿形层次遍历.js
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/*
* @lc app=leetcode.cn id=103 lang=javascript
*
* [103] 二叉树的锯齿形层次遍历
*
* https://leetcode-cn.com/problems/binary-tree-zigzag-level-order-traversal/description/
*
* algorithms
* Medium (55.21%)
* Likes: 354
* Dislikes: 0
* Total Accepted: 101.3K
* Total Submissions: 178.7K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* 给定一个二叉树,返回其节点值的锯齿形层序遍历。(即先从左往右,再从右往左进行下一层遍历,以此类推,层与层之间交替进行)。
*
* 例如:
* 给定二叉树 [3,9,20,null,null,15,7],
*
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
* 返回锯齿形层序遍历如下:
*
*
* [
* [3],
* [20,9],
* [15,7]
* ]
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var zigzagLevelOrder = function(root) {
if(!root) return [];
let res = [], direction = 'left'
let queue = [root]
while(queue.length) {
let arr = [], len = queue.length
while(len > 0) {
let node = queue.shift()
if(direction === 'left') {
arr.push(node.val)
} else {
arr.unshift(node.val)
}
node.left && queue.push(node.left)
node.right && queue.push(node.right)
len--
}
direction = direction === 'left' ? 'right' : 'left'
res.push(arr)
}
return res
};
// @lc code=end