Book 1 Chapter 10.2 Snell's Law Unclear on the Length of Ray Directions for its Proof #1449
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Thanks for your proof. It helped me review some forgotten knowledge.👍 |
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I'm glad it helped ! :) |
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Are you open to moving this issue to a new discussion under the discussion tab? |
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Hi, I also prove this formula at the first time I learnt the book one. I think my proof is more intuitive and needs only senior high school knowledge. I write proof in LaTeX format and post it in my repo for reference. |
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In Chapter 10.2, Snell's Law
The book presents refracted ray formula as
$$R' = R_{\perp}' + R_{\parallel}'$$
where
$$R_{\perp}' = \frac{\eta}{\eta'} \left( R + \cos\theta \hat n \right)$$
$$R_{\parallel}' = - \sqrt{1 - |R_{\perp}'|^2} \hat n$$ $R$ .
for a given incoming ray
The book says
Yet forgets to mention the important details: $R$ and $R'$ are unit vectors.
But to add more confusion, the book in Chapter 4.2 says
In my opinion, the book at least should clarify that$R, R'$ are unit vectors, or present more general expression.
Here is my proof:
Snell's law states that
$$\sin\theta' = \frac{\eta}{\eta'}\sin\theta$$
Assume$R$ and $R'$ are incoming rays and refracted rays respectively obeying Snell's Law. Also, we have $\hat n$ , a unit normal vector, facing against the incoming ray.
Note that we can deconstruct$R'$ via
$$R' = R_{\perp}' + R_{\parallel}'$$ $R_{\perp}'$ is perpendicular to $\hat n$ and $R_{\parallel}'$ is parallel to $\hat n$ .
where
Without loss of generality, assume a unit vector$\hat x$ is in the direction of $R_{\perp}'$ (ie. $\hat x = R_{\perp}' / |R_{\perp}'|$ ).
Then using trigonometry, one can see that
$$R_{\perp}' = |R'|\sin\theta' \hat x $$
$$R_{\parallel}' = - |R'|\cos\theta' \hat n$$
By Snell's law,
$$R_{\perp}' = |R'|\sin\theta' \hat x = |R'|\frac{\eta}{\eta'}\sin\theta \hat x$$
under suitable condition (ie. solution must exists).
Lemma:$\sin\theta \hat x = R/|R| + \cos\theta \hat n$
Consider
$$R_{\perp}$$
$$R = R_\perp + R_\parallel$$
where
Under 'right-hand rule' one can see that$(\hat n \times R) \times \hat n$ is in the direction of $\hat x$ ; hence there exists $\lambda \in \mathbb{R}^+$ such that
$$\lambda \hat x = (\hat n \times R) \times \hat n$$
Then by Lagrange's formula
$$\lambda \hat x = (\hat n \times R) \times \hat n = (\hat n \cdot \hat n)R - (\hat n \cdot R)\hat n = R + |R|\cos \theta \hat n$$
Consider
$$|\lambda \hat x|^2 = \left|R + |R|\cos\theta \hat n\right|^2$$
$$\Rightarrow \lambda^2 = |R|^2 + 2|R|\cos\theta (R \cdot \hat n) + |R|^2 \cos^2 \theta$$
$$\Rightarrow \lambda^2 = |R|^2 - 2|R|^2\cos^2\theta + |R|^2 \cos^2 \theta = |R|^2 - |R|^2 \cos^2 \theta$$
$$\Rightarrow \lambda^2 = |R|^2 \left(1 - \cos^2\theta \right) = |R|^2 \sin^2\theta$$
$$\Rightarrow\lambda = |R| \sin\theta$$
Hence
$$\lambda \hat x = |R| \sin\theta \hat x = R + |R|\cos\theta \hat n$$
$$\sin\theta \hat x = \frac{R}{|R|} + \cos\theta \hat n$$
or
Now we are almost done with the proof.
Back to the proof
Again, consider
$$R_\perp' = |R'| \frac{\eta}{\eta'}\sin \theta \hat x = |R'| \frac{\eta}{\eta'} \left(\frac{R}{|R|} + \cos\theta \hat n\right)$$
by the earlier lemma.
Since$|R'|^2 = |R_\parallel'|^2 + |R_\perp|^2$ ,
$$\therefore R_\parallel' = -\sqrt{|R'|^2 - |R_\perp'|^2}\hat n$$
Conclusion
Thus, final formula for arbitrary length of$R$ and $R'$ are given by
$$R_\perp' = |R'| \frac{\eta}{\eta'} \left(\frac{R}{|R|} + \cos\theta \hat n\right)$$
$$R_\parallel' = -\sqrt{|R'|^2 - |R_\perp'|^2}\hat n$$
which in general not equivalent to the given formula from the book.
However, if$R'$ and $R$ are both unit vector, this reduces to the expression given in the book:
$$R_\perp' = \frac{\eta}{\eta'} \left(R+ \cos\theta \hat n\right)$$
$$R_\parallel' = -\sqrt{1 - |R_\perp'|^2}\hat n$$
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