Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1
/ \ / \
2 3 2 3
[1,2,3], [1,2,3]
Output: true
Example 2:
Input: 1 1
/ \
2 2
[1,2], [1,null,2]
Output: false
Example 3:
Input: 1 1
/ \ / \
2 1 1 2
[1,2,1], [1,1,2]
Output: false
Tags: Tree, Depth-first Search
题意是比较两棵二叉树是否相同,那么我们就深搜比较各个节点即可。
java:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == null && q == null) return true;
if (p == null || q == null) return false;
if (p.val == q.val) {
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
return false;
}
}
kotlin(184ms/100.00%):
class Solution {
fun isSameTree(p: TreeNode?, q: TreeNode?): Boolean {
if (p == null && q == null) return true
if (p == null || q == null) return false
return p.`val` == q.`val` && isSameTree(p.left, q.left) && isSameTree(p.right, q.right)
}
}
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} p
* @param {TreeNode} q
* @return {boolean}
*/
var isSameTree = function(p, q) {
if(p == null && q == null) return true
if(p == null || q == null) return false
if(p.val == q.val) {
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right)
}
return false
};
如果你同我们一样热爱数据结构、算法、LeetCode,可以关注我们 GitHub 上的 LeetCode 题解:LeetCode-Solution