Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary search tree.
Example 1:
Input:
1
/ \
0 2
L = 1
R = 2
Output:
1
\
2
Example 2:
Input:
3
/ \
0 4
\
2
/
1
L = 1
R = 3
Output:
3
/
2
/
1
Tags: Tree
题目要求剪去搜索二叉树中不在所给区间的节点。此题主要考察搜索二叉树的特性,即在任意节点作为根节点,左侧子树的所有节点均小于根节点,右侧子树的所有节点均大于根节点。可以进行深搜,若发现节点值在所给区间左边,则可以剪去此节点的左子树,同理,节点值在区间右边则可以减掉右子树,接着将另一侧的子树根节点代替此节点即可。
Java:
public TreeNode trimBST(TreeNode root, int L, int R) {
if (root == null) {
return null;
}
if (root.val < L) {
return trimBST(root.right, L, R);
}
if (root.val > R) {
return trimBST(root.left, L, R);
}
root.left = trimBST(root.left, L, R);
root.right = trimBST(root.right, L, R);
return root;
}
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