leapyr_function.ipynb

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    "# Task\n",
    "#### An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.\n",
    "#### In the Gregorian calendar, three conditions are used to identify leap years:\n",
    "\n",
    "#### The year can be evenly divided by 4, is a leap year, unless:\n",
    "#### The year can be evenly divided by 100, it is NOT a leap year, unless:\n",
    "#### The year is also evenly divisible by 400. Then it is a leap year.\n",
    "#### This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. Source\n",
    "\n",
    "#### Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.\n",
    "#### Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function."
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     "text": [
      " 2012\n"
     ]
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     "text": [
      "True\n"
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    "def is_leap(year):\n",
    "    leap = False\n",
    "\n",
    "    if (year % 4 == 0) and ((year % 400 == 0) or (year % 100 != 0)):\n",
    "        return True\n",
    "    else:\n",
    "        return leap\n",
    "\n",
    "year = int(input())\n",
    "print(is_leap(year))"
   ]
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      " 2013\n"
     ]
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      "False\n"
     ]
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    "def is_leap(year):\n",
    "    leap = False\n",
    "    \n",
    "    # Write your logic here\n",
    "    if (year % 4 == 0) and ((year % 400 == 0) or (year % 100 != 0)):\n",
    "        return True\n",
    "    else:\n",
    "        return leap\n",
    "\n",
    "year = int(input())\n",
    "print(is_leap(year))"
   ]
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      "Selected Jupyter core packages...\n",
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