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MaximumInSubArray.java
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MaximumInSubArray.java
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import java.util.*;
public class Solution {
public static void main(String[] args) {
int[] arr = firstNegative(new int[] {3,-1, -2, -4, 2 , 3}, 6, 3);
for(int i=0;i<arr.length;i++)
System.out.print(arr[i]);
}
public static int[] firstNegative(int[] arr, int n, int k) {
// Write your code here.
Queue<Integer> l = new LinkedList<>();
int res[] = new int[n - k + 1];
int start=0,end=0;
while(end < n)
{
while(l.size() > 0 && l.peek() < arr[end])
{
l.poll();
}
//Calculation
l.add(arr[end]);
if(end - start + 1 < k)
{
end++;
}
else if(end - start + 1 == k)
{
res[start] = l.peek();
if(arr[start] == l.peek())
{
l.poll();
}
start++;
}
}
return res;
}
/* More optimized
* public static int[] firstNegative(int[] arr, int n, int k) {
// Write your code here.
Queue<Integer> l = new LinkedList<>();
int res[] = new int[n - k + 1];
int start=0,end=0;
for(; end<k-1;end++)
{
while(l.size() > 0 && l.peek() < arr[end])
{
l.poll();
}
//Calculation
l.add(arr[end]);
}
while(end < n)
{
while(l.size() > 0 && l.peek() < arr[end])
{
l.poll();
}
//Calculation
l.add(arr[end++]);
res[start] = l.peek();
if(arr[start] == l.peek())
{
l.poll();
}
start++;
}
return res;
}
*/
}