by Maciej Sikora @maciejsikora
For given function type Fn
, and any type A
(any in this context means we don't restrict the type, and I don't have in mind any type 😉) create a generic type which will take Fn
as the first argument, A
as the second, and will produce function type G
which will be the same as Fn
but with appended argument A
as a last one.
For example,
type Fn = (a: number, b: string) => number
type Result = AppendArgument<Fn, boolean>
// expected be (a: number, b: string, x: boolean) => number
This question is ported from the original article by @maciejsikora