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<h2 class="post-title" itemprop="name headline">Leetcode 2: Add Two Numbers
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<p><strong>难度：Medium</strong></p>
<h3 id="题目描述"><a href="#题目描述" class="headerlink" title="题目描述"></a>题目描述</h3><p>给定两个非空链表来表示两个非负整数。位数按照逆序方式存储，它们的每个节点只存储单个数字。将两数相加返回一个新的链表。</p>
<p>你可以假设除了数字 0 之外，这两个数字都不会以零开头。</p>
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<h3 id="示例"><a href="#示例" class="headerlink" title="示例"></a>示例</h3><figure class="highlight shell"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br></pre></td><td class="code"><pre><span class="line">输入：(2 -> 4 -> 3) + (5 -> 6 -> 4)</span><br><span class="line">输出：7 -> 0 -> 8</span><br><span class="line">原因：342 + 465 = 807</span><br></pre></td></tr></table></figure>
<h3 id="解题思路"><a href="#解题思路" class="headerlink" title="解题思路"></a>解题思路</h3><p>这道题考察的是链表的操作，平常我们加两个数都是从后往前加，而这个反过来即可，进位是往后面进位。</p>
<h3 id="解题代码"><a href="#解题代码" class="headerlink" title="解题代码"></a>解题代码</h3><figure class="highlight java"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br><span class="line">28</span><br><span class="line">29</span><br><span class="line">30</span><br><span class="line">31</span><br><span class="line">32</span><br><span class="line">33</span><br><span class="line">34</span><br><span class="line">35</span><br><span class="line">36</span><br><span class="line">37</span><br><span class="line">38</span><br><span class="line">39</span><br><span class="line">40</span><br><span class="line">41</span><br><span class="line">42</span><br><span class="line">43</span><br></pre></td><td class="code"><pre><span class="line"><span class="comment">/**</span></span><br><span class="line"><span class="comment"> * Definition for singly-linked list.</span></span><br><span class="line"><span class="comment"> * public class ListNode {</span></span><br><span class="line"><span class="comment"> * int val;</span></span><br><span class="line"><span class="comment"> * ListNode next;</span></span><br><span class="line"><span class="comment"> * ListNode(int x) { val = x; }</span></span><br><span class="line"><span class="comment"> * }</span></span><br><span class="line"><span class="comment"> */</span></span><br><span class="line"><span class="class"><span class="keyword">class</span> <span class="title">Solution</span> </span>{</span><br><span class="line"> <span class="function"><span class="keyword">public</span> ListNode <span class="title">addTwoNumbers</span><span class="params">(ListNode l1, ListNode l2)</span> </span>{</span><br><span class="line"> List<Integer> res = <span class="keyword">new</span> ArrayList<>();</span><br><span class="line"> <span class="keyword">int</span> p = <span class="number">0</span>;</span><br><span class="line"> <span class="keyword">while</span> (l1 != <span class="keyword">null</span> && l2 != <span class="keyword">null</span>) {</span><br><span class="line"> <span class="keyword">int</span> temp = l1.val + l2.val + p;</span><br><span class="line"> res.add(temp % <span class="number">10</span>);</span><br><span class="line"> p = temp / <span class="number">10</span>;</span><br><span class="line"> l1 = l1.next;</span><br><span class="line"> l2 = l2.next;</span><br><span class="line"> }</span><br><span class="line"> <span class="keyword">while</span> (l1 != <span class="keyword">null</span>) {</span><br><span class="line"> <span class="keyword">int</span> temp = l1.val + p;</span><br><span class="line"> res.add(temp % <span class="number">10</span>);</span><br><span class="line"> p = temp / <span class="number">10</span>;</span><br><span class="line"> l1 = l1.next;</span><br><span class="line"> }</span><br><span class="line"> <span class="keyword">while</span> (l2 != <span class="keyword">null</span>) {</span><br><span class="line"> <span class="keyword">int</span> temp = l2.val + p;</span><br><span class="line"> res.add(temp % <span class="number">10</span>);</span><br><span class="line"> p = temp / <span class="number">10</span>;</span><br><span class="line"> l2 = l2.next;</span><br><span class="line"> }</span><br><span class="line"> <span class="keyword">if</span> (p != <span class="number">0</span>) {</span><br><span class="line"> res.add(p);</span><br><span class="line"> }</span><br><span class="line"> ListNode head = <span class="keyword">new</span> ListNode(res.get(<span class="number">0</span>));</span><br><span class="line"> ListNode ph = head;</span><br><span class="line"> <span class="keyword">for</span> (<span class="keyword">int</span> i = <span class="number">1</span>; i < res.size(); i++) {</span><br><span class="line"> ph.next = <span class="keyword">new</span> ListNode(res.get(i));</span><br><span class="line"> ph = ph.next;</span><br><span class="line"> }</span><br><span class="line"> <span class="keyword">return</span> head;</span><br><span class="line"> }</span><br><span class="line">}</span><br></pre></td></tr></table></figure>
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