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剑指 Offer II 069. 山峰数组的顶部

题目描述

符合下列属性的数组 arr 称为 山峰数组（山脉数组） ：

• arr.length >= 3
• 存在 i（0 < i < arr.length - 1）使得：
  • arr[0] < arr[1] < ... arr[i-1] < arr[i]
  • arr[i] > arr[i+1] > ... > arr[arr.length - 1]

给定由整数组成的山峰数组 arr ，返回任何满足 arr[0] < arr[1] < ... arr[i - 1] < arr[i] > arr[i + 1] > ... > arr[arr.length - 1] 的下标 i ，即山峰顶部。

 

示例 1：

输入：arr = [0,1,0]
输出：1

示例 2：

输入：arr = [1,3,5,4,2]
输出：2

示例 3：

输入：arr = [0,10,5,2]
输出：1

示例 4：

输入：arr = [3,4,5,1]
输出：2

示例 5：

输入：arr = [24,69,100,99,79,78,67,36,26,19]
输出：2

 

提示：

• 3 <= arr.length <= 104
• 0 <= arr[i] <= 106
• 题目数据保证 arr 是一个山脉数组

 

进阶：很容易想到时间复杂度 O(n) 的解决方案，你可以设计一个 O(log(n)) 的解决方案吗？

 

注意：本题与主站 852 题相同：https://leetcode.cn/problems/peak-index-in-a-mountain-array/

解法

方法一

Python3

class Solution:
    def peakIndexInMountainArray(self, arr: List[int]) -> int:
        left, right = 1, len(arr) - 2
        while left < right:
            mid = (left + right) >> 1
            if arr[mid] > arr[mid + 1]:
                right = mid
            else:
                left = mid + 1
        return left

Java

class Solution {
    public int peakIndexInMountainArray(int[] arr) {
        int left = 1, right = arr.length - 2;
        while (left < right) {
            int mid = (left + right) >> 1;
            if (arr[mid] > arr[mid + 1]) {
                right = mid;
            } else {
                left = mid + 1;
            }
        }
        return left;
    }
}

C++

class Solution {
public:
    int peakIndexInMountainArray(vector<int>& arr) {
        int left = 1, right = arr.size() - 2;
        while (left < right) {
            int mid = (left + right) >> 1;
            if (arr[mid] > arr[mid + 1])
                right = mid;
            else
                left = mid + 1;
        }
        return left;
    }
};

Go

func peakIndexInMountainArray(arr []int) int {
	left, right := 1, len(arr)-2
	for left < right {
		mid := (left + right) >> 1
		if arr[mid] > arr[mid+1] {
			right = mid
		} else {
			left = mid + 1
		}
	}
	return left
}

JavaScript

/**
 * @param {number[]} arr
 * @return {number}
 */
var peakIndexInMountainArray = function (arr) {
    let left = 1;
    let right = arr.length - 2;
    while (left < right) {
        const mid = (left + right) >> 1;
        if (arr[mid] < arr[mid + 1]) {
            left = mid + 1;
        } else {
            right = mid;
        }
    }
    return left;
};

Swift

class Solution {
    func peakIndexInMountainArray(_ arr: [Int]) -> Int {
        var left = 1
        var right = arr.count - 2
        while left < right {
            let mid = (left + right) / 2
            if arr[mid] > arr[mid + 1] {
                right = mid
            } else {
                left = mid + 1
            }
        }
        return left
    }
}