| comments | difficulty | edit_url | tags | |
|---|---|---|---|---|
true |
Easy |
|
Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.
Example 1:
Input: millis = 100
Output: 100
Explanation: It should return a promise that resolves after 100ms.
let t = Date.now();
sleep(100).then(() => {
console.log(Date.now() - t); // 100
});
Example 2:
Input: millis = 200 Output: 200 Explanation: It should return a promise that resolves after 200ms.
Constraints:
1 <= millis <= 1000
async function sleep(millis: number): Promise<void> {
return new Promise(r => setTimeout(r, millis));
}
/**
* let t = Date.now()
* sleep(100).then(() => console.log(Date.now() - t)) // 100
*//**
* @param {number} millis
* @return {Promise}
*/
async function sleep(millis) {
return new Promise(r => setTimeout(r, millis));
}
/**
* let t = Date.now()
* sleep(100).then(() => console.log(Date.now() - t)) // 100
*/