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Mass-flow rate distribution in meshed network #494

Answered by dlohmeier
MikhailSkl asked this question in Q&A
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Dear @MikhailSkl ,
in general, @jkisse is right, but I would like to shift the focus a little: The resistance rates of the two paths through the heat exchangers are extreme. Actually it would make sense if the flow through P2S and P2R would be 0, because there is a resistance of this pipe while there is no resistance in the heat exchanger HE1. So, if there is no pressure drop between J2S and J2R, any flow through P2S and P2R will create a higher pressure drop than that. So, I am not sure what exactly you would like to simulate, but here are some suggestions:

  • Set the loss_coefficient of the heat_exchangers to some values higher than 0 --> if you want to simulate a regulator here, you can …

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@JonasPfeiffer123
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