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06_sum_square_diff.c
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06_sum_square_diff.c
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//https://projecteuler.net/problem=6
/*
The sum of the squares of the first ten natural numbers is,
1^2+2^2+...+10^2=385
The square of the sum of the first ten natural numbers is,
(1+2+...+10)^2=55^2=3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is
3025-385=2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
*/
#include <stdio.h>
int main(){
int sum_of_squares = 0;
int square_of_sum = 0;
for(int i = 1; i <= 100; i++){
sum_of_squares += i*i;
square_of_sum += i;
}
square_of_sum = square_of_sum * square_of_sum;
printf("Difference between the sum of the squares of the first one hundred natural numbers and the square of the sum is %d\n", square_of_sum - sum_of_squares);//25164150
return 0;
}