Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 Output: [1,2,2,3,5,6]
class Solution:
def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
"""
Do not return anything, modify nums1 in-place instead.
"""
while m > 0 or n > 0:
if n == 0 or (m > 0 and nums1[m - 1] >= nums2[n - 1]):
nums1[m + n - 1] = nums1[m - 1]
m -= 1
else:
nums1[m + n - 1] = nums2[n - 1]
n -= 1
# @param {Integer[]} nums1
# @param {Integer} m
# @param {Integer[]} nums2
# @param {Integer} n
# @return {Void} Do not return anything, modify nums1 in-place instead.
def merge(nums1, m, nums2, n)
while m > 0 or n > 0
if n == 0 or (m > 0 and nums1[m - 1] >= nums2[n - 1])
nums1[m + n - 1] = nums1[m - 1]
m -= 1
else
nums1[m + n - 1] = nums2[n - 1]
n -= 1
end
end
end