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88. Merge Sorted Array

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

  • The number of elements initialized in nums1 and nums2 are m and n respectively.
  • You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.

Example:

Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6],       n = 3

Output: [1,2,2,3,5,6]

Solutions (Python)

1. Solution

class Solution:
    def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
        """
        Do not return anything, modify nums1 in-place instead.
        """
        while m > 0 or n > 0:
            if n == 0 or (m > 0 and nums1[m - 1] >= nums2[n - 1]):
                nums1[m + n - 1] = nums1[m - 1]
                m -= 1
            else:
                nums1[m + n - 1] = nums2[n - 1]
                n -= 1

Solutions (Ruby)

1. Solution

# @param {Integer[]} nums1
# @param {Integer} m
# @param {Integer[]} nums2
# @param {Integer} n
# @return {Void} Do not return anything, modify nums1 in-place instead.
def merge(nums1, m, nums2, n)
    while m > 0 or n > 0
        if n == 0 or (m > 0 and nums1[m - 1] >= nums2[n - 1])
            nums1[m + n - 1] = nums1[m - 1]
            m -= 1
        else
            nums1[m + n - 1] = nums2[n - 1]
            n -= 1
        end
    end
end