Find all valid combinations of k
numbers that sum up to n
such that the following conditions are true:
- Only numbers
1
through9
are used. - Each number is used at most once.
Return a list of all possible valid combinations. The list must not contain the same combination twice, and the combinations may be returned in any order.
Input: k = 3, n = 7 Output: [[1,2,4]] Explanation: 1 + 2 + 4 = 7 There are no other valid combinations.
Input: k = 3, n = 9 Output: [[1,2,6],[1,3,5],[2,3,4]] Explanation: 1 + 2 + 6 = 9 1 + 3 + 5 = 9 2 + 3 + 4 = 9 There are no other valid combinations.
Input: k = 4, n = 1 Output: [] Explanation: There are no valid combinations. Using 4 different numbers in the range [1,9], the smallest sum we can get is 1+2+3+4 = 10 and since 10 > 1, there are no valid combination.
2 <= k <= 9
1 <= n <= 60
impl Solution {
pub fn combination_sum3(k: i32, n: i32) -> Vec<Vec<i32>> {
let mut x: i32 = (1 << k) - 1;
let mut ret = vec![];
while x < (1 << 9) {
let comb = (1..=9)
.filter(|&digit| (1 << (digit - 1)) & x != 0)
.collect::<Vec<i32>>();
if comb.iter().sum::<i32>() == n {
ret.push(comb);
}
x += (x & -x) + (1 << ((x >> x.trailing_zeros()).trailing_ones() - 1)) - 1;
}
ret
}
}