Given a directed acyclic graph (DAG) of n
nodes labeled from 0
to n - 1
, find all possible paths from node 0
to node n - 1
and return them in any order.
The graph is given as follows: graph[i]
is a list of all nodes you can visit from node i
(i.e., there is a directed edge from node i
to node graph[i][j]
).
Input: graph = [[1,2],[3],[3],[]] Output: [[0,1,3],[0,2,3]] Explanation: There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.
Input: graph = [[4,3,1],[3,2,4],[3],[4],[]] Output: [[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4],[0,1,4]]
n == graph.length
2 <= n <= 15
0 <= graph[i][j] < n
graph[i][j] != i
(i.e., there will be no self-loops).- All the elements of
graph[i]
are unique. - The input graph is guaranteed to be a DAG.
class Solution:
def allPathsSourceTarget(self, graph: List[List[int]]) -> List[List[int]]:
paths = [[0]]
ret = []
while paths != []:
path = paths.pop()
if path[-1] == len(graph) - 1:
ret.append(path)
continue
for j in graph[path[-1]]:
paths.append(path + [j])
return ret