Given an array of unique integers salary
where salary[i]
is the salary of the employee i
.
Return the average salary of employees excluding the minimum and maximum salary.
Input: salary = [4000,3000,1000,2000] Output: 2500.00000 Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively. Average salary excluding minimum and maximum salary is (2000+3000)/2= 2500
Input: salary = [1000,2000,3000] Output: 2000.00000 Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively. Average salary excluding minimum and maximum salary is (2000)/1= 2000
Input: salary = [6000,5000,4000,3000,2000,1000] Output: 3500.00000
Input: salary = [8000,9000,2000,3000,6000,1000] Output: 4750.00000
3 <= salary.length <= 100
10^3 <= salary[i] <= 10^6
salary[i]
is unique.- Answers within
10^-5
of the actual value will be accepted as correct.
# @param {Integer[]} salary
# @return {Float}
def average(salary)
min_salary = salary.min
max_salary = salary.max
sum_salary = salary.sum
return 1.0 * (sum_salary - min_salary - max_salary) / (salary.length - 2)
end
impl Solution {
pub fn average(salary: Vec<i32>) -> f64 {
let min_salary = salary.iter().min().unwrap();
let max_salary = salary.iter().max().unwrap();
let sum_salary = salary.iter().sum::<i32>();
(sum_salary - min_salary - max_salary) as f64 / (salary.len() - 2) as f64
}
}