You are given a directed graph of n
nodes numbered from 0
to n - 1
, where each node has at most one outgoing edge.
The graph is represented with a given 0-indexed array edges
of size n
, indicating that there is a directed edge from node i
to node edges[i]
. If there is no outgoing edge from node i
, then edges[i] == -1
.
Return the length of the longest cycle in the graph. If no cycle exists, return -1
.
A cycle is a path that starts and ends at the same node.
Input: edges = [3,3,4,2,3] Output: 3 Explanation: The longest cycle in the graph is the cycle: 2 -> 4 -> 3 -> 2. The length of this cycle is 3, so 3 is returned.
Input: edges = [2,-1,3,1] Output: -1 Explanation: There are no cycles in this graph.
n == edges.length
2 <= n <= 105
-1 <= edges[i] < n
edges[i] != i
use std::collections::HashMap;
impl Solution {
pub fn longest_cycle(edges: Vec<i32>) -> i32 {
let mut visited = vec![false; edges.len()];
let mut nodes = HashMap::new();
let mut ret = -1;
for i in 0..edges.len() {
if visited[i] {
continue;
}
let mut i = i;
let mut count = 1;
nodes.clear();
while edges[i] != -1 {
if let Some(&x) = nodes.get(&i) {
ret = ret.max(count - x);
break;
} else if visited[i] {
break;
}
visited[i] = true;
nodes.insert(i, count);
i = edges[i] as usize;
count += 1;
}
}
ret
}
}