You are given a 0-indexed integer array nums
. A pair of indices (i, j)
is a bad pair if i < j
and j - i != nums[j] - nums[i]
.
Return the total number of bad pairs in nums
.
Input: nums = [4,1,3,3] Output: 5 Explanation: The pair (0, 1) is a bad pair since 1 - 0 != 1 - 4. The pair (0, 2) is a bad pair since 2 - 0 != 3 - 4, 2 != -1. The pair (0, 3) is a bad pair since 3 - 0 != 3 - 4, 3 != -1. The pair (1, 2) is a bad pair since 2 - 1 != 3 - 1, 1 != 2. The pair (2, 3) is a bad pair since 3 - 2 != 3 - 3, 1 != 0. There are a total of 5 bad pairs, so we return 5.
Input: nums = [1,2,3,4,5] Output: 0 Explanation: There are no bad pairs.
1 <= nums.length <= 105
1 <= nums[i] <= 109
use std::collections::HashMap;
impl Solution {
pub fn count_bad_pairs(nums: Vec<i32>) -> i64 {
let mut count = HashMap::new();
let mut ret = 0;
for i in 0..nums.len() {
ret += i as i64 - count.get(&(i as i32 - nums[i])).unwrap_or(&0);
count
.entry(i as i32 - nums[i])
.and_modify(|c| *c += 1)
.or_insert(1);
}
ret
}
}