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10extra.c
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10extra.c
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// Banker's Algorithm
#include <stdio.h>
int main()
{
// P0, P1, P2, P3, P4 are the Process names here
int n, m, i, j, k;
n = 5; // Number of processes
m = 3; // Number of resources
int alloc[5][3] = {{0, 1, 0}, // P0 // Allocation Matrix
{2, 0, 0}, // P1
{3, 0, 2}, // P2
{2, 1, 1}, // P3
{0, 0, 2}}; // P4
int max[5][3] = {{7, 5, 3}, // P0 // MAX Matrix
{3, 2, 2}, // P1
{9, 0, 2}, // P2
{2, 2, 2}, // P3
{4, 3, 3}}; // P4
int avail[3] = {3, 3, 2}; // Available Resources
int f[n], ans[n], ind = 0;
for (k = 0; k < n; k++)
{
f[k] = 0;
}
int need[n][m];
for (i = 0; i < n; i++)
{
for (j = 0; j < m; j++)
need[i][j] = max[i][j] - alloc[i][j];
}
int y = 0;
for (k = 0; k < 5; k++)
{
for (i = 0; i < n; i++)
{
if (f[i] == 0)
{
int flag = 0;
for (j = 0; j < m; j++)
{
if (need[i][j] > avail[j])
{
flag = 1;
break;
}
}
if (flag == 0)
{
ans[ind++] = i;
for (y = 0; y < m; y++)
avail[y] += alloc[i][y];
f[i] = 1;
}
}
}
}
printf("Following is the SAFE Sequence\n");
for (i = 0; i < n - 1; i++)
printf(" P%d ->", ans[i]);
printf(" P%d", ans[n - 1]);
printf("\n");
return (0);
}