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036 Valid Sudoku.py
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036 Valid Sudoku.py
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'''
36. Valid Sudoku
https://leetcode.com/problems/valid-sudoku/
Determine if a 9 x 9 Sudoku board is valid.
Only the filled cells need to be validated according to the following rules:
Each row must contain the digits 1-9 without repetition.
Each column must contain the digits 1-9 without repetition.
Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.
Note:
A Sudoku board (partially filled) could be valid but is not necessarily solvable.
Only the filled cells need to be validated according to the mentioned rules.
Example 1:
Input: board =
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: true
Example 2:
Input: board =
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8.
Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Constraints:
board.length == 9
board[i].length == 9
board[i][j] is a digit 1-9 or '.'.
'''
# 10 '1's, bit mask to check if a number appeared
DEFAULT_MASK = 0x3ff
def isCharValid(c: str, mask: int):
if c == '.':
return True, mask
i = int(c)
# Flip mask[i]
mask ^= (1<<i)
# If appears only once, mask[i] should be 0
if (mask & (1<<i)) != 0:
return False, mask
return True, mask
class Solution:
def isValidSudoku(self, board: List[List[str]]) -> bool:
# Check rows
for r in range(9):
mask = DEFAULT_MASK
for c in range(9):
isValid, mask = isCharValid(board[r][c], mask)
if not isValid:
return False
# Check columns
for c in range(9):
mask = DEFAULT_MASK
for r in range(9):
isValid, mask = isCharValid(board[r][c], mask)
if not isValid:
return False
# Check 3*3 cells
for i in range(3):
for j in range(3):
mask = DEFAULT_MASK
for r in range(i*3, i*3+3):
for c in range(j*3,j*3+3):
isValid, mask = isCharValid(board[r][c], mask)
if not isValid:
return False
return True