407. Trapping Rain Water II

[mah-shamim]

Topics: Array, Breadth-First Search, Heap (Priority Queue), Matrix

Given an m x n integer matrix heightMap representing the height of each unit cell in a 2D elevation map, return the volume of water it can trap after raining.

Example 1:

• Input: heightMap = [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]]
• Output: 4
• Explanation: After the rain, water is trapped between the blocks.
  We have two small ponds 1 and 3 units trapped.
  The total volume of water trapped is 4.

Example 2:

• Input: heightMap = [[3,3,3,3,3],[3,2,2,2,3],[3,2,1,2,3],[3,2,2,2,3],[3,3,3,3,3]]
• Output: 10

Constraints:

• m == heightMap.length
• n == heightMap[i].length
• 1 <= m, n <= 200
• 0 <= heightMap[i][j] <= 2 * 104

[mah-shamim]

The "Trapping Rain Water II" problem is a challenging computational problem that requires us to compute the volume of water trapped after raining on a 2D elevation map represented as a matrix. This problem extends the classic "Trapping Rain Water" problem to two dimensions, making the solution more complex due to the need to consider water flow in all directions.

Key Points

1. Matrix Representation: The heightMap matrix contains the elevation of each cell.
2. Boundary Constraints: Water cannot flow out of the boundary cells.
3. Heap Data Structure: A min-heap (priority queue) is used to simulate the water levels dynamically.
4. Visited Matrix: To prevent revisiting cells, we track visited nodes.

Approach

The solution leverages a Breadth-First Search (BFS) approach, guided by a priority queue (min-heap):

1. Add all boundary cells to the min-heap and mark them as visited.
2. Process cells in increasing height order:
   • For each cell, attempt to "trap" water in its neighbors.
   • Push neighboring cells into the heap with updated height values.
3. Accumulate the trapped water volume based on the height difference between the current cell and its neighbors.

Plan

1. Initialization:

   • Define matrix dimensions and edge cases.
   • Initialize a min-heap for boundary cells.
   • Create a visited matrix.

2. Insert Boundary Cells:

   • Push all boundary cells into the heap with their height values.
   • Mark them as visited.

3. BFS Traversal:

   • While the heap is not empty, extract the cell with the smallest height.
   • Check all its neighbors and calculate trapped water:
     • If the neighbor is lower, the height difference contributes to trapped water.
     • Update the neighbor's height to the current cell's height if higher.
   • Push the neighbor into the heap and mark it visited.

4. Return Result:

   • The accumulated water volume represents the trapped rainwater.

Let's implement this solution in PHP: 407. Trapping Rain Water II

<?php
/**
 * @param Integer[][] $heightMap
 * @return Integer
 */
function trapRainWater($heightMap) {
    $m = count($heightMap);
    $n = count($heightMap[0]);

    if ($m < 3 || $n < 3) {
        return 0;
    }

    $directions = [[1, 0], [-1, 0], [0, 1], [0, -1]];
    $minHeap = new SplPriorityQueue();
    $visited = array_fill(0, $m, array_fill(0, $n, false));

    // Add the boundary cells to the priority queue
    for ($i = 0; $i < $m; $i++) {
        for ($j = 0; $j < $n; $j++) {
            if ($i == 0 || $i == $m - 1 || $j == 0 || $j == $n - 1) {
                $minHeap->insert([$i, $j, $heightMap[$i][$j]], -$heightMap[$i][$j]);
                $visited[$i][$j] = true;
            }
        }
    }

    $waterTrapped = 0;

    while (!$minHeap->isEmpty()) {
        list($x, $y, $h) = $minHeap->extract();
        foreach ($directions as $direction) {
            $nx = $x + $direction[0];
            $ny = $y + $direction[1];

            if ($nx >= 0 && $nx < $m && $ny >= 0 && $ny < $n && !$visited[$nx][$ny]) {
                $visited[$nx][$ny] = true;
                $waterTrapped += max(0, $h - $heightMap[$nx][$ny]);
                $minHeap->insert([$nx, $ny, max($h, $heightMap[$nx][$ny])], -max($h, $heightMap[$nx][$ny]));
            }
        }
    }

    return $waterTrapped;
}

// Example Usage
$heightMap1 = [[1, 4, 3, 1, 3, 2], [3, 2, 1, 3, 2, 4], [2, 3, 3, 2, 3, 1]];
$heightMap2 = [[3, 3, 3, 3, 3], [3, 2, 2, 2, 3], [3, 2, 1, 2, 3], [3, 2, 2, 2, 3], [3, 3, 3, 3, 3]];

echo trapRainWater($heightMap1) . "\n"; // Output: 4
echo trapRainWater($heightMap2) . "\n"; // Output: 10
?>

Explanation:

1. Boundary Initialization:

   • All boundary cells are added to the heap to form the outer walls of the container.

2. Heap Extraction:

   • Extract the cell with the lowest height, ensuring that water flows only outward, not inward.

3. Neighbor Exploration:

   • For each neighbor:
     • Check if it’s within bounds and unvisited.
     • Calculate the water trapped as max(0, currentHeight - neighborHeight).
     • Push the updated neighbor height into the heap.

4. Accumulate Water:

   • Add the trapped water for each neighbor to the total.

Example Walkthrough

Input:

$heightMap = [
    [1, 4, 3, 1, 3, 2],
    [3, 2, 1, 3, 2, 4],
    [2, 3, 3, 2, 3, 1]
];

Steps:

1. Boundary Cells:

   • Push cells from the boundary into the heap with their heights:
     • Example: (0, 0, 1), (0, 1, 4), etc.

2. Heap Traversal:

   • Extract cell (0, 0, 1) (lowest height).
   • Check neighbors, calculate water trapped:
     • For neighbor (1, 0): Water trapped = max(0, 1 - 3) = 0.

3. Trapped Water:

   • Continue processing until all cells are visited:
     • Total trapped water = 4.

Time Complexity

1. Heap Operations:

   • Each cell is pushed and popped from the heap once: O(m * n * log(m * n)).

2. Neighbor Iteration:

   • Each cell has up to 4 neighbors: O(m * n).

Total Complexity:

O(m * n * log(m * n))

Output for Example

$heightMap = [
    [1, 4, 3, 1, 3, 2],
    [3, 2, 1, 3, 2, 4],
    [2, 3, 3, 2, 3, 1]
];
echo trapRainWater($heightMap); // Output: 4

The "Trapping Rain Water II" problem demonstrates the power of advanced data structures like priority queues combined with BFS. By simulating the flow of water in a 2D elevation map, we can efficiently compute the total trapped water. This solution is optimal for handling large matrices due to its logarithmic heap operations.

[basharul-siddike]

Thanks for solving the problem of "Trapping Rain Water II"

[mah-shamim]

Thanks