Do not print strict-mode commands when set -x is on

[olivergondza]

Consider doing trap '{ s=$?; set +x; } 2>/dev/null; echo >&2 "$0: Error on line "$LINENO": $BASH_COMMAND"; exit $s' ERR to prevent all commands to be printed in case the shell failed while set -x is on. Additionally, other traps are printed, which might be desirable, and the suggested snippet prevents that.

++ s=1
++ echo './script.sh: Error on line 127: COMMAND_LINE_HERE'
./script.sh: Error on line 127: COMMAND_LINE_HERE
++ exit 1
+ rm -rf /tmp/temp-dir.zM0

With this change on, the script fails with:

./script.sh: Error on line 127: COMMAND_LINE_HERE