Print keyword blocks print as a function

[hen6003]

Print being a keyword currently stops you using "print" as a function on a type using with_fn

Example code:

#[derive(Clone, CustomType)]
#[rhai_type(extra = Self::build_extra)]
struct Type {}

impl Type {
    fn build_extra(builder: &mut TypeBuilder<Self>) {
        builder
            .with_name("Type")
            .with_fn("print", |s: &str| println!("{}", s));
    }
}

fn main() {
    let mut engine = Engine::new();

    engine.register_type::<Type>();

    let mut scope = Scope::new();

    scope.push("t", Type {});

    println!(
        "{:?}",
        engine.run_with_scope(&mut scope, "t.print(\"hello world!\"")
    );
}

Outputs:

Err(ErrorParsing(Reserved("print"), 1:3))

[schungx]

That's correct, because print is a keyword. You can easily override it by setting the to_string function instead. print uses to_string to format the output.

[rawhuul]

Hey @hen6003, this might be helpful