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这里的else可以去掉 #1165
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def is_prime(n):
if n<2:
return False
if n==2:
return True
for m in range(2,int(n**0.5)+1):
if (n%m)==0:
return False
else:
return True
for i in range(80,110):
if is_prime(i):
print(i)
变成下面这样:
def is_prime(n):
if n < 2:
return False
if n == 2:
return True
for m in range(2, int(n**0.5) + 1):
if n % m == 0:
return False
return True # 将这一行移出循环,并直接放在循环之后
for i in range(80, 110):
if is_prime(i):
print(i)
以下是GPT的解释
在这段代码中,else 语句的用法是正确的,但是它的位置可能会导致一些混淆。让我来解释一下:
当 for 循环结束时,如果没有在循环中遇到 return 语句(也就是没有返回值),那么就会执行 else 语句块。在这个特定的代码中,else 语句块紧跟在 for 循环后面,意味着只要 for 循环中没有 return 语句被执行,就会执行 else 语句块。
在这个例子中,else 语句块实际上不是必要的,因为它永远不会被执行。这是因为 for 循环中的 return 语句会在找到第一个除数时结束函数的执行,导致函数的返回值是 False。如果没有找到除数,for 循环会正常结束,然后返回 True,所以 else 语句块永远不会执行。
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