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HtmlEasy With Servlet implementation in GAE not working #7

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GoogleCodeExporter opened this issue Mar 30, 2015 · 0 comments
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Hi,

i just started using htmleasy, i have been trying to configure htmleasy as 
servlet impl in google appengine , but no luck, after configuring and 
registering class , when i try to access a jsp page it shows , resources not 
avaiable.

Is Filter is essentials (there is not documentation stat that it is required), 
following is config:

       <servlet>
        <servlet-name>resteasy-servlet</servlet-name>
        <servlet-class>
            com.googlecode.htmleasy.HtmleasyServletDispatcher
                </servlet-class>
        <init-param>
            <param-name>javax.ws.rs.Application</param-name>
            <param-value>com.test.resteasygae.config.AppConfig</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>resteasy-servlet</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <jsp-property-group>
        <description>Common config for all the JSP</description>
        <url-pattern>/*</url-pattern>
        <el-ignored>false</el-ignored>
    </jsp-property-group>


and my app config :

public class AppConfig extends Application {

    @Override
    public Set<Class<?>> getClasses() {
        Set<Class<?>> services = new HashSet<Class<?>>();

        services.add(MainController.class);
        services.addAll(HtmleasyProviders.getClasses());

        return services;
    }
}


controller path

        @Path("/")
    @GET
    public View hanldeRequest() {
        return new View("index.jsp");
    }


and the result :

could not find resource at path http://localhost:8888/index.jsp


when i use it with filters instead of servlets , it working fine, so i just 
wanted to know , wether filter is must ?

can u help ?

What version of the product are you using?
0.7


Original issue reported on code.google.com by ramesh.l...@a-cti.com on 15 Jul 2013 at 2:28

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