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Hi, |
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Answered by
mosflex
Oct 27, 2022
Replies: 1 comment 1 reply
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Ok I understood now when I tried to call ShowPopupAsync() in a loop. |
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Answer selected by
mosflex
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Ok I understood now when I tried to call ShowPopupAsync() in a loop.
When the popup is dismissed first time and recalled second time it keep always the same result.
So to have another result, you have to reset the popup before calling ShowPopupAsync() second time