The type 'T' must be a reference type in order to use it as parameter 'TValue' in the generic type or method 'Utils.SerializeJsonCopy<TValue>(TValue, JsonTypeInfo<TValue>, bool)'

The type 'T' must be a reference type in order to use it as parameter 'TValue' in the generic type or method 'SafeStructMallocHandle<return_value_json>.ValueAsJson<TValue>(JsonTypeInfo<TValue>, string?)'

Process completed with exit code 1.

Converting null literal or possible null value to non-nullable type.