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brian-rose committed Dec 18, 2023
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4 changes: 2 additions & 2 deletions courseware/grey-radiation-climlab.html
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Expand Up @@ -1555,8 +1555,8 @@ <h3>Initialize a model in <code class="docutils literal notranslate"><span class
</div>
</div>
<p>Compare these to the analytical solutions for radiative equilibrium with <span class="math notranslate nohighlight">\(\epsilon = 0.58\)</span>:</p>
<div class="amsmath math notranslate nohighlight" id="equation-dd61ab52-3e26-4a2d-a488-3da299a9e6c5">
<span class="eqno">(8.1)<a class="headerlink" href="#equation-dd61ab52-3e26-4a2d-a488-3da299a9e6c5" title="Permalink to this equation">#</a></span>\[\begin{align}
<div class="amsmath math notranslate nohighlight" id="equation-42d46b99-03e1-4c2d-925a-7275fe02fec3">
<span class="eqno">(8.1)<a class="headerlink" href="#equation-42d46b99-03e1-4c2d-925a-7275fe02fec3" title="Permalink to this equation">#</a></span>\[\begin{align}
T_s &amp;= 296.4 \text{ K} \\
T_0 &amp;= 262.3 \text{ K} \\
T_1 &amp;= 233.8 \text{ K} \\
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4 changes: 2 additions & 2 deletions courseware/radiative-transfer.html
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Expand Up @@ -647,8 +647,8 @@ <h3>Transmissitivity<a class="headerlink" href="#transmissitivity" title="Permal
<h3>Emissivity<a class="headerlink" href="#emissivity" title="Permalink to this heading">#</a></h3>
<p>The second term is the net change in the beam due to <strong>emissions</strong> in the layer.</p>
<p>We can the define the <strong>emissivity</strong> <span class="math notranslate nohighlight">\(\epsilon_0\)</span> of the layer analogously</p>
<div class="amsmath math notranslate nohighlight" id="equation-c26e9978-f136-475a-9c28-e07a7a718fef">
<span class="eqno">(9.1)<a class="headerlink" href="#equation-c26e9978-f136-475a-9c28-e07a7a718fef" title="Permalink to this equation">#</a></span>\[\begin{align}
<div class="amsmath math notranslate nohighlight" id="equation-2de0a0c4-2d5a-43aa-9d10-47cbea619eca">
<span class="eqno">(9.1)<a class="headerlink" href="#equation-2de0a0c4-2d5a-43aa-9d10-47cbea619eca" title="Permalink to this equation">#</a></span>\[\begin{align}
\epsilon_{0} &amp;= 1 - \exp(-\Delta \tau) \\
&amp;= 1 - t_{0}
\end{align}\]</div>
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8 changes: 4 additions & 4 deletions courseware/sympy-greenhouse.html
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Expand Up @@ -551,8 +551,8 @@ <h2>2. Coding up the 2-layer grey gas model in sympy<a class="headerlink" href="
<section id="longwave-emissions">
<h3>Longwave emissions<a class="headerlink" href="#longwave-emissions" title="Permalink to this heading">#</a></h3>
<p>Let’s denote the emissions from each layer as</p>
<div class="amsmath math notranslate nohighlight" id="equation-98560edd-b777-4f84-94bf-4467f84546c9">
<span class="eqno">(7.1)<a class="headerlink" href="#equation-98560edd-b777-4f84-94bf-4467f84546c9" title="Permalink to this equation">#</a></span>\[\begin{align}
<div class="amsmath math notranslate nohighlight" id="equation-cdbadd96-47a8-4b39-9e15-358e0e2b7416">
<span class="eqno">(7.1)<a class="headerlink" href="#equation-cdbadd96-47a8-4b39-9e15-358e0e2b7416" title="Permalink to this equation">#</a></span>\[\begin{align}
E_s &amp;= \sigma T_s^4 \\
E_0 &amp;= \epsilon \sigma T_0^4 \\
E_1 &amp;= \epsilon \sigma T_1^4
Expand Down Expand Up @@ -1183,8 +1183,8 @@ <h4>Radiative equilibrium means net absorption is ZERO in the atmosphere<a class
</div>
</div>
<p>In more familiar notation, the radiative equilibrium solution is thus</p>
<div class="amsmath math notranslate nohighlight" id="equation-ea011407-0813-439e-8d03-859d555bf6f5">
<span class="eqno">(7.2)<a class="headerlink" href="#equation-ea011407-0813-439e-8d03-859d555bf6f5" title="Permalink to this equation">#</a></span>\[\begin{align}
<div class="amsmath math notranslate nohighlight" id="equation-8225b370-e669-4a4b-b287-47dbc1b3f8c8">
<span class="eqno">(7.2)<a class="headerlink" href="#equation-8225b370-e669-4a4b-b287-47dbc1b3f8c8" title="Permalink to this equation">#</a></span>\[\begin{align}
T_s &amp;= T_e \left( \frac{2+\epsilon}{2-\epsilon} \right)^{1/4} \\
T_0 &amp;= T_e \left( \frac{1+\epsilon}{2-\epsilon} \right)^{1/4} \\
T_1 &amp;= T_e \left( \frac{ 1}{2 - \epsilon} \right)^{1/4}
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