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Hulksmash Big O Analysis
Andrew Burke edited this page Jan 10, 2025
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JCSU Unit 4 Problem Set 2 (Click for link to problem statements)
- 💡 Difficulty: Easy
- ⏰ Time to complete: 10-15 mins
- 🛠️ Topics: Complexity Analysis, Iteration, Modulus Operations
Understand what the interviewer is asking for by analyzing the behavior and efficiency of the function
hulk_smash()
.
Questions:
- What is the time complexity of
hulk_smash()
based on the input size (n)? - What is the space complexity of the function?
- How would a dictionary-based lookup for divisibility checks affect the time complexity?
Match this problem to known complexity analysis concepts and scenarios.
-
Iterative Processing:
- The function iterates through (1) to (n), performing a constant number of operations for each element.
-
Modulus Operations:
- Each modulus operation ((i % 3), (i % 5)) is a constant-time operation ((O(1))).
-
Output List Construction:
- A list of size (n) is created, requiring linear space.
-
Dictionary-Based Optimization:
- Using a dictionary for logic centralization does not affect the overall iteration count or complexity.
Plan the analysis by breaking down the function's behavior step by step.
- Determine the cost of iterating through (1) to (n).
- Evaluate the impact of performing modulus operations during each iteration.
- Identify the memory required for storing the output list.
- Assess whether auxiliary space (e.g., temporary variables or data structures) is used.
- Analyze how using a dictionary impacts readability and runtime.
- Determine whether the dictionary-based approach affects asymptotic complexity.
Implement the analysis with clear justifications.
-
Overall Complexity: The time complexity of
hulk_smash()
is O(n). -
Reasoning:
- The function iterates over (n) elements.
- For each element, it performs a constant number of modulus operations ((i % 3), (i % 5), and possibly (i % 15)).
- Each modulus operation is (O(1)), so the total complexity is (O(n)).
-
Overall Complexity: The space complexity of
hulk_smash()
is O(n). -
Reasoning:
- The function constructs a list
answer
of size (n), which requires (O(n)) space. - No other data structures or additional memory are used, so the auxiliary space is constant ((O(1))).
- The function constructs a list
-
Time Complexity:
- Dictionary lookups for divisibility logic would still involve modulus operations ((O(1))).
- The total iteration count over (n) elements dominates the complexity, which remains (O(n)).
-
Advantages:
- Centralizes the logic for handling multiple divisibility conditions.
- Improves code readability and maintainability.
-
Disadvantages:
- Slight overhead for dictionary setup and lookups, though this does not affect asymptotic complexity.
Review the scenarios and validate with examples.
-
Input:
n = 5
- Expected Output: ["1", "2", "Fizz", "4", "Buzz"]
- Observed Complexity: (O(n)) with (O(n)) space.
-
Input:
n = 15
- Expected Output: ["1", "2", "Fizz", "4", "Buzz", "Fizz", ..., "FizzBuzz"]
- Observed Complexity: (O(n)), with (n) modulus checks and a list of size (n).
Evaluate the performance of
hulk_smash()
and trade-offs between iterative logic and dictionary-based lookup.
-
Time Complexity:
- (O(n)), as the function iterates through (n) elements, performing constant-time operations for each.
-
Space Complexity:
- (O(n)), as the output list stores (n) elements.
-
Current Approach:
- Simple and efficient for small to moderate (n).
- Logic is directly written into the iteration loop.
-
Dictionary-Based Lookup:
- Better for extensibility and maintaining complex divisibility conditions.
- Slightly more overhead for dictionary setup, but complexity remains (O(n)).