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[SYCL] Return nullptr when allocation size is zero in usm allocator #12765
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// RUN: %{build} -o %t.out | ||
// RUN: %{run} %t.out | ||
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#include <sycl/sycl.hpp> | ||
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using namespace sycl; | ||
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template <usm::alloc alloc_kind> void test(queue &q) { | ||
sycl::usm_allocator<int, alloc_kind> ua(q); | ||
int *p = ua.allocate(0); | ||
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assert(!p && "Our implementation of usm_allocator is expected to return a " | ||
"null pointer when allocation " | ||
"size is zero."); | ||
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ua.deallocate(p, 0); | ||
} | ||
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int main() { | ||
queue q; | ||
auto dev = q.get_device(); | ||
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if (dev.get_info<info::device::usm_host_allocations>()) { | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Why do we only test "host" here? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I'm not sure how adding more allocation types will increase the test coverage of this change. Nevertheless, I've expanded the test to also check for zero-sized shared allocations. usm::alloc::device is not supported by usm_allocator so, I've skipped that.
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test<usm::alloc::host>(q); | ||
} | ||
if (dev.get_info<info::device::usm_shared_allocations>()) { | ||
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test<usm::alloc::shared>(q); | ||
} | ||
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return 0; | ||
} |
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I think this is fine, but another option is to simply remove the assert. From an API perspective, the important thing is that you can call allocate with a zero size and that you can then call deallocate on the returned pointer, all without any exception being raised. It's not important whether or not the returned pointer is null.