This is an implementation of IBM's Quantum Experience in simulation; a 5-qubit quantum computer with a limited set of gates "the world’s first quantum computing platform delivered via the IBM Cloud". Their implementation is available at http://www.research.ibm.com/quantum/.
This code allows you to execute code printed from the Quantum Composer in IBM's syntax. It is much easier to dig into the internals of how the quantum computer computes by seeing and tracing the linear algebra representation of gates and states and their interactions as desired–for IBM's examples or for one's own code.
100% of the examples on the IBM tutorial are provided here, tested for and supported, and many addition tests and examples are provided. In fact, the implementation of the 5-qubit quantum computer simulator is only 675 lines, with approximately twice as many lines of test programs and examples provided.
Check out any of the test functions for example usage, and the Programs
class contains many example programs in IBM's syntax all available in one place.
If you make use of this work, please cite my paper available on the physics arXiv as Quintuple: a Python 5-qubit quantum computer simulator to facilitate cloud quantum computing. For the making of story of this code, along with some pointers to resources on quantum computation, check out my blog post.
from QuantumComputer import *
ghz_example_code="""h q[0];
h q[1];
x q[2];
cx q[1], q[2];
cx q[0], q[2];
h q[0];
h q[1];
h q[2];"""
qc=QuantumComputer()
qc.execute(ghz_example_code)
Probability.pretty_print_probabilities(qc.qubits.get_quantum_register_containing("q0").get_state())
This will print
|psi>=0.70710678118654724|000>+-0.70710678118654724|111>
Pr(|000>)=0.500000; Pr(|111>)=0.500000;
Or, using the swap Qubits example IBM tutorial Section IV, Page 2
swap_example_code="""x q[2];
cx q[1], q[2];
h q[1];
h q[2];
cx q[1], q[2];
h q[1];
h q[2];
cx q[1], q[2];
measure q[1];
measure q[2];"""
qc.reset()
qc.execute(swap_example_code)
Probability.pretty_print_probabilities(qc.qubits.get_quantum_register_containing("q2").get_state())
will print
|psi>=|10>
Pr(|10>)=1.000000;
<state>=-1.000000
We'll continue with this example in pure python below.
Note: using IBM's measurment code measure q[0];
will actually collapse the state, but for convenience the internal state before collapse is stored in qubit.get_noop(). Nature doesn't give this to us, but I can give it to you!
Quantum computing operations can also be done in pure python, either with the QuantumComputer machinery or by directly manipulating gates.
# Swap Qubits example IBM tutorial Section IV, Page 2
qc=QuantumComputer()
qc.apply_gate(Gate.X,"q2")
qc.apply_two_qubit_gate_CNOT("q1","q2")
qc.apply_gate(Gate.H,"q1")
qc.apply_gate(Gate.H,"q2")
qc.apply_two_qubit_gate_CNOT("q1","q2")
qc.apply_gate(Gate.H,"q1")
qc.apply_gate(Gate.H,"q2")
qc.apply_two_qubit_gate_CNOT("q1","q2")
qc.measure("q1")
qc.measure("q2")
Probability.pretty_print_probabilities(qc.qubits.get_quantum_register_containing("q1").get_state())
Will print
|psi>=|10>
Pr(|10>)=1.000000;
<state>=-1.000000
Note that states are combined by using the Kronecker product. Gates that operate on entangled states are composed from single qubit gates by the Kronecker product of the gate with the Identity. See the internals of qc.apply_gate
or qc.apply_two_qubit_gate_CNOT
for general examples, or feel free to use them instead.
# Swap Qubits example IBM tutorial Section IV, Page 2
q1=State.zero_state
q2=State.zero_state
q2=Gate.X*q2
new_state=Gate.CNOT2_01*np.kron(q1,q2)
H2_0=np.kron(Gate.H,Gate.eye)
H2_1=np.kron(Gate.eye,Gate.H)
new_state=H2_0*new_state
new_state=H2_1*new_state
new_state=Gate.CNOT2_01*new_state
new_state=H2_0*new_state
new_state=H2_1*new_state
new_state=Gate.CNOT2_01*new_state
Probability.pretty_print_probabilities(new_state)
Will print
|psi>=0.99999999999999967|10>
Pr(|10>)=1.000000;
<state>=-1.000000
This final manner of working with the library provides the most complete mathematical understanding of what's going on. Any individual state or gate can be printed, and it is clear how entanglement is represented as this is not done under the hood in this scenario.