Solution #417
Solution #417
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Great job on implementing the core functionality of the getBullsAndCows function! 👍 The game logic appears to be working as expected. Just remember to keep an eye on the minor suggestions such as refining input validation and considering alternative coding styles for future improvements. These can enhance the readability and robustness of your code. Keep coding and refining your skills! 🚀
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| const { getBullsAndCows } = require('./modules/getBullsAndCows.js'); | ||
| const { checkIsValidUserInput } = require('./modules/checkIsValidUserInput.js'); | ||
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| const numberToGues = generateRandomNumber(); |
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There is a typo in the variable name 'numberToGues'. It should be 'numberToGuess' to correctly reflect its purpose.
| function question() { | ||
| rl.question('What is your number?', (userAnswer) => { | ||
| if (!checkIsValidUserInput(userAnswer)) { | ||
| console.log('Number must include 4 unique digits'); | ||
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| return question(); | ||
| } | ||
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| const result = getBullsAndCows(userAnswer, numberToGues); | ||
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| console.log( | ||
| `Your number: ${userAnswer} ||`, | ||
| `Random number: ${numberToGues}`, | ||
| result, | ||
| ); | ||
| rl.close(); |
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The game does not continue after a valid guess is made. You should only close the readline interface when the user has guessed the correct number (all bulls). Otherwise, the game should continue by calling question() again.
| `Random number: ${numberToGues}`, | ||
| result, | ||
| ); | ||
| rl.close(); |
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After printing the result, the game ends regardless of whether the player won or lost. You may want to add a condition to check if the user has won (e.g., all digits are bulls) before closing the readline interface.
| for (let i = 0; i < userInput.length; i++) { | ||
| const check = userInput.slice(1); | ||
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| if (userInput[0] === '0') { | ||
| return false; | ||
| } | ||
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| if (check.includes(userInput[0])) { | ||
| return false; | ||
| } | ||
| } |
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The current implementation of the loop and checks inside it may not correctly validate the input. The slice is being done on each iteration but only the first character of userInput is being compared and checked for duplicates. This means that only the first character is being validated for uniqueness and not being '0', which is incorrect. Instead, you should iterate over each character in userInput and check if it is unique within the string and not '0'.
| return false; | ||
| } | ||
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| if (isNaN(userInput)) { |
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The isNaN function can give incorrect results when used with strings that represent numbers. For example, isNaN('1234') will return false, which is correct, but isNaN('0123') will also return false, which may not be the intended behavior if leading zeros are not allowed. Consider using a regular expression to ensure that the input is a four-digit number with no leading zeros and each digit is unique.
| function generateRandomNumber() { | ||
| /* Write your code here */ | ||
| let digits = ['1', '2', '3', '4', '5', '6', '7', '8', '9']; | ||
| let number = digits[Math.floor(Math.random() * digits.length)]; | ||
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| digits = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'].filter( | ||
| (d) => !number.includes(d), | ||
| ); | ||
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| while (number.length < 4) { | ||
| const randomIndex = Math.floor(Math.random() * digits.length); | ||
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| number += digits[randomIndex]; | ||
| digits.splice(randomIndex, 1); | ||
| } | ||
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| return Number(number); |
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The function generateRandomNumber generates a random number with unique digits, which is good. However, the current implementation has a potential issue. It always generates a number starting with a digit between 1 and 9, and then includes 0 in the subsequent digits. If the game rules allow the first digit to be 0, this function would not comply with the rules. Ensure the game rules are being followed correctly.
| digits.splice(randomIndex, 1); | ||
| } | ||
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| return Number(number); |
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The function returns the number as a Number type. If the first randomly generated digit is '0' after modifying the function to include '0' as a possible first digit, Number(number) will remove it, which may not be the desired outcome if the leading zero is significant. Consider returning the number as a string if leading zeroes are important.
| const userInputToString = userInput.toString().split(''); | ||
| const numberToGuessToString = numberToGuess.toString().split(''); |
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It's a good practice to ensure that the input parameters are of expected types before performing operations on them. Consider adding a type check for 'userInput' and 'numberToGuess' to ensure they are numbers and handle any potential type-related errors.
| const userInputToString = userInput.toString().split(''); | ||
| const numberToGuessToString = numberToGuess.toString().split(''); |
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You are converting both 'userInput' and 'numberToGuess' to strings and then splitting them into arrays. This is a valid approach, but to make the code more concise, you could perform these operations in a single step using Array.from, like so: Array.from(userInput.toString()).
| for (let i = 0; i < userInputToString.length; i++) { | ||
| if (userInputToString[i] === numberToGuessToString[i]) { | ||
| result.bulls++; | ||
| } else if (numberToGuessToString.includes(userInputToString[i])) { | ||
| result.cows++; | ||
| } | ||
| } |
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The current implementation of the loop is correct, but you might consider using a more functional approach with Array methods like 'forEach' for better readability. However, this is more of a stylistic choice and the current loop is perfectly acceptable if you prefer this style.
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