[이지민] - CCW, 전구와 스위치, 케빈 베이컨의 6단계 법칙, 함께 블록 쌓기 #173
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bngsh
approved these changes
Sep 11, 2023
| @@ -0,0 +1,19 @@ | |||
| ''' | |||
| 1도 모르겠습니다. | |||
| 수학 다 까먹었습니다.. | |||
| for i in range(0, n - 1): | ||
| if now_1[i] != after[i]: | ||
| num_1 += 1 | ||
| now_1[i] = 1 - now_1[i] |
Comment on lines
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| for i in range(n): | ||
| for j in range(h + 1): | ||
| if dp[i][j]: | ||
| for s in students[i]: | ||
| if j + s <= h: | ||
| dp[i + 1][j + s] = (dp[i + 1][j + s] + dp[i][j]) % 10007 |
| q = deque([n]) | ||
| visited = [0 for _ in range(len(bacons) + 1)] | ||
| num = 1 | ||
| while q: |
soopeach
approved these changes
Sep 11, 2023
| @@ -0,0 +1,19 @@ | |||
| ''' | |||
| 1도 모르겠습니다. | |||
| 수학 다 까먹었습니다.. | |||
| p2_x, p2_y = map(int, input().split()) | ||
| p3_x, p3_y = map(int, input().split()) | ||
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| res = p1_x * p2_y + p2_x * p3_y + p3_x * p1_y - (p2_x * p1_y + p3_x * p2_y + p1_x * p3_y) |
| for i in range(0, n - 1): | ||
| if now_1[i] != after[i]: | ||
| num_1 += 1 | ||
| now_1[i] = 1 - now_1[i] |
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| n, m = map(int, input().split()) | ||
| bacons = defaultdict(list) |
| if dp[i][j]: | ||
| for s in students[i]: | ||
| if j + s <= h: | ||
| dp[i + 1][j + s] = (dp[i + 1][j + s] + dp[i][j]) % 10007 |
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+= 연산 후에
%= 연산하는 것보다
이렇게 한 줄로 나타내는게 더 편해서 이렇게 구하신건가요??
There was a problem hiding this comment.
넵! 이게 더 연산이 빠를 것 같기두 하고요??
jhg3410
approved these changes
Sep 11, 2023
Comment on lines
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| ''' | ||
| 1도 모르겠습니다. | ||
| 수학 다 까먹었습니다.. |
| global bacons | ||
| q = deque([n]) | ||
| visited = [0 for _ in range(len(bacons) + 1)] | ||
| num = 1 |
| now_1 = before[:] | ||
| num_1 = 0 | ||
| for i in range(0, n - 1): | ||
| if now_1[i] != after[i]: |
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📌 from issue #170 📌
📋문제 목록📋
📍추가로 해결한 문제📍
📝메모
이번주 짱 어렵네요,,